Multiple choice Questions of Zoology Topic Linkage and Recombination MCQ with Answers ( Linkage and Recombination ) for NEET, GATE, AIAPGET, NEET MDS, NEET PG, DNB PDCET, AIIMS SS, PGIMER (Other), AIIMS PG and many more competitive examinations.
MCQ on Mutation | Linkage and Recombination | Zoology Quiz
1. Rearrangement of DNA is known as
( a ) replication
( b ) transcription
( C ) recombination
( d ) None of these
Ans. c
2. Who coined the term ‘ crossing over ” ?
( a ) Darwin
( b ) Griffith
( c ) Morgan
( d ) None of these
Ans. c
3. Type of recombination are
( a ) homologous recombination
( b ) restricted recombination
( c ) site – specific recombination
( d ) Both ( a ) and ( c )
Ans. d
4. Who described the breakage of chromatids ?
( a ) Morgan
( b ) Stern and Hotta
( c ) Both ( a ) and ( b )
( d ) Darwin
Ans. b
5. Lambda integrase enzyme is involved in which of the following recombination ?
( a ) Homologous recombination
( b ) Site – specific recombination
( c ) Both ( a ) and ( b )
( d ) None of the above
Ans. b
6. Number of linkage in a polynucleotide would be
( a ) same as number of nucleotides
( b ) twice as number of nucleotides
( c ) one less than the number of nucleotides
( d ) one only
Ans. d
7. Linked genes are separate due to the
( a ) recombination
( b ) mutation
( c ) crossing over
( d ) None of these
Ans. c
8. Morgan coined the term ‘ linkage ‘ to describe
( a ) generation of non – parental gene combinations
( b ) association of genes on a chromosome
( c ) physical status of gene combinations
( d ) generation of parental gene combinations
Ans. b
9. Recombination describes
( a ) generation of parental gene combinations
( b ) generation of non – parental gene combinations
( c ) generation of both parental and non – parental gene combinations
( d ) All of the above
Ans. b
10. Alfred Strutevant to measure the distance between genes and mapped their position on the chromosome used the frequency of
( a ) recombination between gene pairs on the two different chromosomes
( b ) recombination between gene pairs on the same chromosome
( c ) gene pairing on two different chromosomes
( d ) gene pairing on the same chromosomes
Ans. b
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11. Linkage and cytological maps for the same chromosome
( a ) are both based on mutant phenotypes and recombination data
( b ) may have different sequences of genes
( c ) have both the same sequences of genes and intergenic distances
( d ) have the same sequences of genes , but different intergenic distances
Ans. d
12. Variability may originate during meiosis due to
( a ) crossing over
( b ) chromosomal aberations
( c ) polyploidy
( d ) mutations
Ans. a
14. Complete linkage in Drosophila males
( a ) results in the absence of cross overs
( b ) results in total absence of genetic recombination
( c ) means that sperms produced are only of two types
( d ) results in all the genes in a particular linkage group mapping at the same point
Ans. a
15. Maize has 10 pairs of chromosomes . How many linkage groups will be present if all the genes are mapped ?
( a ) 15
( b ) 10
( c ) 20
( d ) 40
Ans. b
16. A pair of genes are linked if their recombination frequency in test cross is
( a ) 75 %
( b ) 50 %
( c ) 100 %
( d ) lower than 50 %
Ans. d
17. According to chromosomal theory of linkage of Morgan and Castle
( a ) strength of linkage between two successive genesis inversely proportional to the distance between two genes
( b ) genes lie in a linear order in the chromosomes
( c ) linked genes are arranged in cis or trans manner cis – arrangement AB/ab brings coupling ( parental combinations ) while trans – arrangement Ab/ab brings recombinations ( repulsions )
( d ) All of the above
Ans. d
18. Linkage in Drosophila was first discovered by
( a ) Bateson and Punnett
( b ) Bridges
( c ) Morgan
( d ) Sturtevant
Ans. c
19. Complete linkage is observed in
( a ) birds
( b ) lizards
( c ) frog
( d ) Drosophila
Ans. d
20. A linkage group is explained as
( a ) different groups of genes located on the same chromosomes
( b ) all the linked genes of a chromosome pair
( c ) all the linked genes of a chromosome
( d ) None of the above
Ans. b
Mutation MCQ | Point Mutation Involves MCQ
21. When two genes are located very close to each other in a chromosomes ?
( a ) No crossing over is seen between them
( b ) Only double cross over can take place
( c ) Hardly any crossing over can be detected
( d ) Percentage of crossing over is very high
Ans. c
22. The test cross of a F individual with genotype ( ++ / ab ) produced the following offspring ++ / ab 10 , ab / ab 10 , + a / ab 40 , + b / ab 40. Based on this data , predict the configuration of F , heterozygous .
( a ) trans – configuration
( b ) cis – configuration
( c ) Both ( a ) and ( b )
( d ) None of the above
Ans. a
23. Linkage map of X – chromosome of fruitfly has 66 map units with yellow body gene ( y ) at one end and bobbed hair ( b ) at other . The recombination frequency between y and b gene would be
( a ) 66 %
( b ) > 50 %
( c ) <=50 %
( d ) 100 %
Ans. c
24. If two genes a ‘ and ‘ b ‘ are linked and show 20 % recombination , the proportion of gametes produced in F1 by a dihybrid ++ / ab derived from a cross between ++ / ++ and ab / ab would be
( a ) + + 20 : ab 20 + a 20 + b 20
( b ) + + 80 : ab 20
( c ) ++ 50 : ab 50
( d ) ++ 40 : ab 40: + a10 + b10
Ans. d
25. Consider the following statements regarding linkage . I. The linked genes are located on the same chromosome . II. Crossing over between linked genes is rare . III. Linked genes are always inherited together . IV. Linkage affects the percentage of homozygosity Select the correct statements .
( a ) I and III
( b ) I and II
( c ) II, III and IV
( d ) I, Ill and IV
Ans. a
mcq on chromosome mapping | linkage results in mcq | linkage prevents which condition
26. The first attempt to show linkage in plants was done in
( a ) Zea mays
( b ) Oenothera amarckiana
( c ) Pisum sativum
( d ) Lathyrus odoratus
Ans. d
27. Which of the following genetic events represent a case of incomplete linkage ?
( a ) Inheritance between gene , so that one gene prevents expression of other genes
( b ) A condition , in which the phenotype effect of a gene’s simultaneously expressed in the heterozygote
( c ) Occasional separation of two genes on the same chromosome by a recombinant event
( d ) Expression of heterozygous phenotype , which is distinct form and often intermediate to that of either parent
Ans. c
28. In tomato , three pairs of genes are located on a chromosome of these each two are linked . There is 8 % recombination between the genes for tallness ( T ) and smooth surface ( S ) . There is 20 % recombination between tallness and oval – shape ( O ) of the fruit and 12 % between oval – shape fruit and smooth fruit surface . The correct sequence of the genesis
( a ) S – O – T
( b ) S – T – O
( c ) T – S – O
( d ) O – T – S
Ans. c
29. In a linear chromosome , map distances between 4 loci is as follows a – b 10 % , a – d 3 % , b – c 4 % and a – c 6 % . The cross over frequency between cand d is
( a ) 4-12 %
( b ) 3 or 9 %
( c ) 9 %
( d ) 3 %
Ans. d
30. Genetic maps of chromosomes are based on the frequency of
( a ) non – disjunction
( b ) translocation
( c ) dominance
( d ) genetic recombination
Ans. d
Mutation Multiple Choice Questions and Answers | Linkage Prevents MCQ
31. In rabbit , two recessive genes produce a solid body colour and long hair in contrast to dominant spotted body colour and short hair . The result of a cross between heterozygous spotted short haired rabbit to solid long haired rabbit gives spotted , short haired 48 , spotted long haired 5 , solid short haired 7 , solid long haired 40 , total 100. In terms of cross over units how far are there two genes on the chromosome ?
( a ) 40 map units
( b ) 7 map units
( c ) 12 map units
( d ) 48 map units
Ans. c
32. One centimorgan is equal to recombination frequency of
( a ) 1
( b ) 0.1
( c ) 10
( d ) 0.01
Ans. d
33. Individuals homozygous for cd genes were crossed with wild type ++ . The F dihybrid thus , produced was test crossed . It produced progeny in the following ratio +4900 ; + d115 ; cd 880 : C + 105 . What is the distance between cand d genes ?
( a ) 47 units
( b ) 88 units
( C ) 11 units
( d ) 5.75 units
Ans. c
34. AB genes are linked . What is genotype of the progeny in cross between AB / ab and ab / ab ?
( a ) AABB and aabb
( b ) AaBb and aabb
( c ) AAbb and aaBB
( d ) AaBb and AaBb
Ans. b
35. Number of linkage groups in Pisum sativum is
( a ) 2
( b ) 5
( c ) 7
( d ) 9
Ans. c
36. Linkage decreases frequency of
( a ) recessive alleles
( b ) dominant alleles
( c ) hybridisation
( d ) Both ( b ) and ( c )
Ans. c
37. In order to remain linked , the distance between two genes should not increase beyond
( a ) 10 map units
( b ) 20 map units
( c ) 40 map units
( d ) 50 map units
Ans. c
38. Two dominant non allelic genes are 50 map units apart The linkage is
( a ) cis – type
( b ) trans – type
( c ) complete
( d ) absent / incomplete
Ans. d
39. In a dihybrid cross , two recessive genes showed 10 % recombinations . The distance between two genes is
( a ) 10 map units
( b ) 20 map units
( c ) 30 map units
( d ) 40 map units
Ans. a
what are the types of linkages mcq | mcq on linkage in drosophila | linkage and recombination neet questions
40. Crossing over took place in
( a ) one strand stage
( b ) two strand stage
( c ) three strand stage
( d ) four strand stage
Ans. d
41. One chromosome of a homologous pair carries the genes J and K. The other chromosome of the pair carries the genes j and k at corresponding loci . Crossing over results in exchange of chromosome segments and production of gametes with new combinations of genes . A ‘ recombinant type gamete resulting from this cross over might contain
( a ) genes J and K
( b ) genes j and K
( c ) genes J and K
( d ) genes j and k
Ans. b
43. Individual homozygous for cd genes were crossed with crossed and progenies produced in following ratio wild types ( + ) . The F hybrids thus , produced was test + + – 450 , cd – 440 , + d – 58 , + c – 54 Calculate the distance between cand d genes .
( a ) 5.75 units
( b ) 11.2 units
( c ) 45 units
( d ) 44 units
Ans. b
44. If gene frequency between genes a and c 2 % , b and c 13 % , b and d 4 % , a and b15 % , c and d 19 % . What will be the sequence of these genes in a chromosome ?
( a ) a, b , c , d
( b ) a , c, b, d
( c ) d , b , a , c
( d ) a , d, b, c
Ans. b
45. The genetic maps are used as a starting point in the sequencing of whole genomes as in the case of
( a ) human project
( b ) human gene sequencing project
( c ) human genome sequencing project
( d ) All of the above
Ans. c
46. Linked genes are separated due to
( a ) recombination
( b ) mutation
( c ) crossing over
( d ) None of these
Ans. d
47. Which of the following is suitable for experiment on linkage ?
( a ) aaBB x aaBB
( b ) AABB xaabb
( c ) AaBb x AaBb
( d ) AAbb x AaBB
Ans. b
48. Cis – trans expression of genes is an example of
( a ) mutation
( b ) intergenic crossing over
( c ) intragenic crossing over
( d ) cytoplasmic inheritance
Ans. c
49. Crossing over is advantageous because it brings about
( a ) linkage
( b ) stability
( c ) variation
( d ) inbreeding
Ans. c
50. Recombination is involved in the process of
( a ) cytokinesis
( b ) crossing over
( c ) spindle formation
( d ) chromosomal duplication
Ans. b
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